You asked: How many ways can 7 beads be strung on a necklace with a clasp?

How many ways can 7 beads can be arranged to form a necklace?

2520. 5040.

How many ways 8 different beads can be arranged to form a necklace?

2520 Ways 8 beads of different colours be strung as a necklace if can be wear from both side.

What are number of ways in which 10 beads can be arranged to form a necklace?

Answer: This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.

How many necklaces of 10 beads each can be made from 20 beads of different Colours?

This is easy: count all permutations of 10 beads, 10!, then divide by 20 because we counted each permutation 10 times due to rotation, and counted each of these twice because you can flip the necklace over. Thus the answer is 10!/20 = 181440.

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How many ways 5 different beads can be arranged to form a necklace?

So, we have to divide 24 by 2. Therefore the total number of different ways of arranging 5 beads is 242=12 .

How many ways can 12 beads be arranged on a bracket?

12 different beads can be arranged among themselves in a circular order in (12-1)!= 11! Ways. Now, in the case of necklace, there is not distinction between clockwise and anti-clockwise arrangements.

How many different ways can the 8 persons be seated in a circular table?

ways, where n refers to the number of elements to be arranged. = 5040 ways.

How many bracelets can be made by stringing 9 different colored beads together?

by stringing together 9 different coloured beads one can make 9! (9 factorial ) bracelet. 9! = 9×8×7×6×5×4×3×2×1 = 362880 ways.

How many ways can eight beads no two of which are the same be arranged on a chain with a clasp?

2520 Ways 8 beads of different colours be strung as a necklace if can be wear from both side.

How many times can the word computer be arranged?

The number of ways the letters of the word COMPUTER can be rearranged is. 40320. 40319. 40318.

How many ways can the 7 persons be seated in a circular table?

Since in this question we have to arrange persons in a circle and 7 persons have to be arranged in a circle so that every person shall not have the same neighbor. Hence there are 360 ways to do the above arrangement and therefore the correct option is A. So, the correct answer is “Option A”.

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